Average of All Indexes of Array

 let array_1 = [1, 7, 9, 12, 6, 10, 2, 11, 9, 8];
    let average;
    let total = 0;
    for(var i=0; i<array_1.length; i++){
          total = ((total + array_1[i]));
    }
        
    average = (total/(array_1.length));
    console.log(average);

Comments

Post a Comment

Popular posts from this blog

JavaScript Coding Challenge-8

 Write a program which removes 0 from prefix but not suffix..        e.g., - if, i/p - 300, (o/p - 300)        if, i/p - 003, (o/p - 3) _______________________________________  let original_num; let result; function removeZeros(number){       if(number%10 == 0){           result = original_num;       }else{           result = (number%10);       }       console.log(result); } original_num = 009; removeZeros(original_num);
Read more

Largest and Lowest Number of the Array using JavaScript

  let array_1 = [7, 9, 3, 2, 0, 10, 90, 21, 12, 87, 11, 22, 8];     let array_2 = [7, 9, 3, 2, 0, 10, 90, 21, 12, 87, 11, 22, 8, 4, 1, 0];         let largest_number = array_1[0];     let lowest_number = array_2[0];     // loop to find largest number of the array..     for(var i=0; i<array_1.length; i++){              if(largest_number<array_1[i]){                    largest_number = array_1[i];              }     }     // loop to find lowest number of the array..     for(var k=0; k<array_2.length; k++){              if(lowest_number > array_2[k]){     ...
Read more